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大好評のシリーズ"Lippincott's Illustrated Reviews"の「薬理学」が、内容を全面的にアップデートして改訂された。前版と同様に、箇条書き形式、500枚のフルカラー図版、同シリーズの他の巻との相互参照、及び125問の復習問題を採用し、医科薬理学の重要事項に関する大量の複雑な情報を素早くレビューし理解することができる構成となっている。
さらに、新版では本書専用のウェブサイト(thePoint)を新たに設け、全ての図版と検索機能の付いた本編全文を購入者にオンラインで無料提供する。
さらに、新版では本書専用のウェブサイト(thePoint)を新たに設け、全ての図版と検索機能の付いた本編全文を購入者にオンラインで無料提供する。
Book Description
Lippincott's Illustrated Reviews: Pharmacology, Fourth Edition enables rapid review and assimilation of large amounts of complex information about the essentials of medical pharmacology. Clear, sequential pictures of mechanisms of action actually show students how drugs work, instead of just telling them. As in previous editions, the book features an outline format, over 500 full-color illustrations, cross-references to other volumes in the series, and over 125 review questions. Content has been thoroughly updated, and a new chapter covers toxicology.New to this edition will be a companion Website containing all of the illustrations, fully searchable text, and an interactive question bank.
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カスタマーレビュー
最も参考になったカスタマーレビュー
形式:ペーパーバック
This book is nicely designed considering the needs of Undergraduates.
Absolutely this is a fast track if you need to revise soon material Soon!
Absolutely this is a fast track if you need to revise soon material Soon!
Amazon.com で最も参考になったカスタマーレビュー (beta)
Amazon.com:
24個のレビュー
8 人中、8人の方が、｢このレビューが参考になった｣と投票しています。
Slightly below average textbook
2010/1/28
形式:ペーパーバック
Overall, there are a lot of mistakes in this textbook that our professors specifically pointed out. It was annoying to find so many mistakes because it undercuts your confidence in the book itself. Further the chapters were not always organized the same and each drug could have been broken down more clearly and succinctly. There are some strengths though, it had nice pictures and side effects were labeled for many of the big drugs using helpful diagrams. I don't feel like this book worked for me because I need material that I can trust more than helpful diagrams, but everyone is different though. If the diagrams really help you sink it all in then by all means enjoy!
7 人中、7人の方が、｢このレビューが参考になった｣と投票しています。
Full of Errors
2011/1/14
形式:ペーパーバック
I was disappointed with the many errors in this text. During every section, our instructors have to send out a list of corrections in Lippincott's. Pain-in-the-butt. Katzung's Review isn't perfect, but is far superior to this book. -Doc In Training
9 人中、7人の方が、｢このレビューが参考になった｣と投票しています。
Buy Katzung instead.
2011/1/12
形式:ペーパーバック
I have to disagree with the other reviewers- this book is ballsack. It's full of errors, the questions suck, and there are like 4 at the end of each chapter. There is very little room for inaccurate medical texts in my library. I have replaced this book with Katzung and Trevor's Review and you should too. It takes a minimal amount of competency to write/edit these review books- I hope whoever put this book together is treating their cocaine addiction w/ propranolol. Here are a few errors from chapter 1:
1. On page 18, under item number 2, it should read "excretion rate" not "excretion ratio".
2. The equation at the top of page 21 C=C0-e^(-kt) is wrong; here's why:
if dC/dt=-kC
then dC/C=-kdt
and 'dC/C='-kdt, integrating from C0 to C and 0 to t respectively,
we get lnC- lnC0=-kt or lnC=lnC0-kt
taking the exponential.... e^(lnC)=e^(lnC0-kt) == C=e^lnC0 * e^(-kt) <<< ------------ author confused this log rule?
simplifying leaves us: C=C0 * e^(-kt)
3. In the answer to question 1.6, there is an error: the calculation should be Vd = 100 mg/ 20 mcg/mL (not mg) = 100 mg/ 20 mg/L
Math errors are particularly insidious because the uninitiated (read: med students) generally fail to catch them. For example, clueless med student that I am, had I not been doing pharmacokinetics research, I would've never spotted #2.
1. On page 18, under item number 2, it should read "excretion rate" not "excretion ratio".
2. The equation at the top of page 21 C=C0-e^(-kt) is wrong; here's why:
if dC/dt=-kC
then dC/C=-kdt
and 'dC/C='-kdt, integrating from C0 to C and 0 to t respectively,
we get lnC- lnC0=-kt or lnC=lnC0-kt
taking the exponential.... e^(lnC)=e^(lnC0-kt) == C=e^lnC0 * e^(-kt) <<< ------------ author confused this log rule?
simplifying leaves us: C=C0 * e^(-kt)
3. In the answer to question 1.6, there is an error: the calculation should be Vd = 100 mg/ 20 mcg/mL (not mg) = 100 mg/ 20 mg/L
Math errors are particularly insidious because the uninitiated (read: med students) generally fail to catch them. For example, clueless med student that I am, had I not been doing pharmacokinetics research, I would've never spotted #2.
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